The outer circumference of the top of a large hemispherical iron bowl is 565.2 cm and the bowl is 6 cm thick. What will be the volume (in cm3) of the iron required to make this bowl? (Use π = 3.14.)
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e 285312.96.
Outer circumference = 565.2 cm
2 × 3.14 × R = 565.2
R = 90 cm (outer radius)
Thickness = 6 cm
Inner radius r = 90 – 6 = 84 cm
Volume of iron = (2/3) × 3.14 × (R³ – r³) = (2/3) × 3.14 × (90³ – 84³) = 285312.96