SSC CHSL 2024 PYQ — Question 75

The correct answer is option 4 i.e. 2 : $\sqrt{3}$.

The perimeter of an equilateral triangle(P) = 3 × side

⇒ P = 3 × 16 = 48 cm

Now,

Median = $\sqrt3 \over2$ × a

Median = $\sqrt3 \over2$ × 16 = 8$\sqrt3$ cm

An equilateral triangle has three equal medians thus,

The sum of median = 3 × 8$\sqrt3$ = 24$\sqrt3$ cm

Thus,

Required ratio = Perimeter/Sum of medians = $48 \over {24\sqrt3}$ = $2\over {\sqrt3}$ = 2 : $\sqrt3$