SSC CGL 2024 PYQ — Question 67

The correct answer is option 1 i.e. $1\over 100a^4$.​​​​

The mean proportional (or geometric mean) of two numbers, a and b, is the number m such that:

m$^2$ = a × b

In this problem, we're given:

a = 4a$^2$

b = x

m = 1/5a

Substituting these values into the formula, we get:

⇒ (1/5a)$^2$ = 4a$^2$ × x

⇒ 1/25a$^2$ =   4a$^2$ × x

To solve for x , we can isolate it by dividing both sides of the equation by  4a$^2$ :

⇒ x =  (1/25a$^2$ )/  4a$^2$ 

This simplifies to:

⇒ x = 1/100a$^4$

Therefore, the value of x is 1/ 100a$^4$.