SSC CHSL 2025 PYQ — Question 52

SSC CHSL - 19 Nov 2025 - Shift 3 • Quantitative Aptitude • Q52

The length and breadth of a rectangle are in the ratio 14:11, respectively, and the perimeter of the rectangle is 150 cm. If the area of the rectangle is equal to the area of the top surface of a solid cylinder, then find the curved surface area of the cylinder given that its radius is 105% of its height.

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Correct answer: D

Explanation

Given:

Length of rectangle : Width = 14 : 11

Perimeter of rectangle = 150 cm

Radius of cylinder = 105% of height

By formula:

Perimeter = 2(l + b)

Area of ​​rectangle = l × b

Top surface area of ​​cylinder = πr²

Curved surface area of ​​cylinder = 2πrh

Let

Length = 14x

Width = 11x

2(14x + 11x) = 150

2(25x) = 150

50x = 150

x = 3

Length = 42 cm

Width = 33 cm

Area of ​​rectangle = 42 × 33 = 1386 cm²

Now

πr² = 1386

22/7 × r² = 1386

r² = 441

r = 21 cm

Radius = 105% × Height

21 = 1.05h

h = 20 cm

Curved surface area= 2πrh= 2 × 22/7 × 21 × 20= 2640 cm²