SSC CHSL 2025 PYQ — Question 67

SSC CHSL - 15 Nov 2025 - Shift 2 • Quantitative Aptitude • Q67

The length and breadth of a rectangle are in the ratio 14:11, respectively, and the perimeter of the rectangle is 150 cm. If the area of the rectangle is equal to the area of the top surface of a solid cylinder, then find the curved surface area of the cylinder given that its radius is 105% of its height.

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Correct answer: A

Explanation

Given:

Length of rectangle : Width = 14 : 11

Perimeter of rectangle = 150 cm

Area of ​​upper surface of cylinder = Area of ​​rectangle

Radius of cylinder = 105% of height

By formula:

Perimeter = 2(l + b)

Let l = 14x, b = 11x

2(14x + 11x) = 150

50x = 150

x = 3

Length = 14 × 3 = 42

Breadth = 11 × 3 = 33

Area of ​​rectangle = l × b

Area of ​​rectangle = 42 × 33 = 1386

Area of ​​circle = πr²

πr² = 1386

r² = 1386 × 7 / 22 = 21

Radius = 105% × Height

21 = 1.05h

h = 20

Curved surface area of ​​the cylinder = 2πrh

Curved surface area = 2 × 22/7 × 21 × 20 = 2640 cm²