SSC CPO 2024 PYQ — Question 104

SSC CPO - 29 June 2024 - Shift 3 • Quantitative Aptitude • Q104

The lenghth of a side equilateral tringle is 18cm. The area ( in cm2) of the region lying between the circumcircle and incircle of tringle is [use pi = 22/7]

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e  25447\frac{4}{7}.

Side of the equilateral triangle = 18 cm

Radius of circum - circle R = 18/√3 cm

Radius of in - circle r = 18/2√3 = 9/√3 cm

The area of the region lying between the circumcircle and incircle of tringle = π (R2 – r2)  

= π (R + r) (R-r)

= (22/7) × (18/√3 + 9/√3) (18/√3 - 9 /√3)

= (22/7) × 27/√3 × 9/√3

= (81 × 22)/7

= 1782/7 cm²

=254(4/7) cm2