The least number which is exactly divisible by 27, 36, 56, 12 and 10?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 7560.
Prime factorization of each number
27 = ( 33)
36 = ( 22 × 32)
56 = ( 23 × 7)
12 = ( 22 ×3 )
10 = ( 2 × 5)
LCM = 23 × 33 × 51 × 71
LCM = 8 × 27 × 5 × 7
LCM = 7560
The least number that is exactly divisible by 27, 36, 56, 12, and 10 is 7560.