The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15, and 18 is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 364.
LCM (6, 9, 15 and 18) = 90
⇒ x = 7K
The number that is divisible by 90 and leaves the remainder 4 must be greater than 90.
When we put K = 13, x = 91 (gives remainder = 1)
Similarly, put K = 52, x = 364 (gives remainder = 4)
Hence, Required number = 364