SSC CHSL 2025 PYQ — Question 58

SSC CHSL - 14 Nov 2025 - Shift 3 • Quantitative Aptitude • Q58

The largest four-digit number which when divided by 4, 7, or 13 leaves a remainder of 3 in each case is:

Show answer & explanation

Correct answer: B

Explanation

Given:

The remainder when dividing a number by 4, 7, and 13 = 3

Requires the largest 4-digit number

Formula:

If the number is N, then N is exactly divisible by 3, 4, 7, and 13.

LCM(4, 7, 13) = 364

Largest 4-digit number = 9999

9999 − 3 = 9996

Now divide 9996 by 364.

364 × 27 = 9828

N − 3 = 9828

N = 9828 + 3

N = 9831