SSC CGL 2019 PYQ — Question 57

SSC CGL Tier II - Quant 13th Sep. 19 • Quantitative Aptitude • Q57

The internal diameter of a hollow hemispherical vessel is 2.4 cm. It is made of a steel sheet which is 0.5 cm thick. What is the total surface area (in cm2) of the vessel?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is 4 i.e. 612.75π

Explanation :

Internal diameter of hollow hemispherical vessel = 24 cm 

Internal radius (r)=24/2=12 cm

External Radius (R)= r + thickness of sheet 

                               = 12 + 0.5 = 12.5 cm

Surface area of internal vessel = 2π × r²=2π × 12² = 288π  

Surface area of external vessel = 2π R² = 2π(12.5)² = 312.5

Surface area of ring = π  (R² - r²) 

                                 = π (12.5² - 12²)

                                 =π (156.25 - 144)

                                 = 12.25π  

T.S.A = 288π + 312.5 π + 12.25π

         = 612.75π