The income of A is 48% more than of B and the income of C is 50% of the combined income of A and B. By what per cent is the income of A more than that of C? (Correct to one decimal place)
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 19.4.
Let the income of B be 100.
Income of A = 148% of 100 = 148
Income of C = 50% of (100 + 148)
⇒ ½ × 248 = 124
Now, required percentage = [(148 - 124)/124] × 100
⇒ 100 × 24/124 = 19.35 ≈ 19.4%