SSC GD 2025 PYQ — Question 41

SSC GD Const 2025 (English) - 25 Feb 2025 - Shift 2 • Quantitative Aptitude • Q41

The greatest number, which divides 711 and 1040 to leave 48 and 20 respectively as remainders, is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 51.

711 − 48 = 663

1040 − 20 = 1020

HCF of 663 and 1020 = 51