The greatest number, by which when the numbers 1658 and 2038 are divided, the remainder are 7 and 6, respectively, is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 127.
The first number = (1658 - 7) = 1651
The second number = (2038 - 6) = 2032
H.C.F of two numbers
⇒ 1651 = 1 × 13 × 127
⇒ 2032 = 2 × 2 × 2 × 2 × 127
H.C.F = 127
So, if we divide 1658 and 2032 by 127 we will get 7 and 6 as remainder