The given table shows the number of visitors to the Christmas party and the New Year party organised by Bhide's Cafe and Mehta's Cafe.
| Name of cafe | Visitors(Christmas party) | Visitors (New Year Party) |
| Bhide's cafe | 559 | 1118 |
| Mehta's cafe | 666 | 1024 |
What percentage more of visitors visited Mehta's Cafe to Bhide's Cafe (correct to two decimals places)?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 0.78%.
Total visitors in Bhide's cafe = 559 + 1118 = 1677
Total visitors in Mehta's cafe = 666 + 1024 = 1690
Required percentage = [(1690 - 1677)/1677] × 100
⇒ 100 × 13/1677 = 0.78%