The given table shows the number of candidates who appeared (both male and female) in a Public Examination and the percentage of those who qualified in the examination from two states X and Z. Few values are missing in the table (indicated by ------). You will be required to fill them up according to the question.
| Year | State X | State Z | ||
| No. of appeared candidates | Percentage of qualified candidates | No. of appeared candidates | Percentage of qualified candidates | |
| 2008 | 480 | 70% | ------ | 70% |
| 2009 | 560 | 75% | ------ | 80% |
| 2010 | ------ | 60% | 650 | 50% |
| 2011 | 450 | 89% | 720 | 72% |
| 2012 | 790 | ------ | 660 | ------ |
The number of appeared candidates from State Z increased by 100% from 2008 to 2009. If the total number of qualified candidates from State Z in 2008 and 2009 together is 552, what is the number of appeared candidates from State Z in 2009?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 480.
Let the number of appeared candidates from State Z in 2008 be 100x
So, the number of appeared candidates from State Z in 2009 = 200x
Then, = 552
⇒ 70x + 160x = 552
⇒ 230x = 552
⇒ 200x = × 200 = 480