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SSC Selection Post 2020 PYQ — Question 56

SSC Selection Post - Graduation Level 2020 - 9 Nov 2020 - Shift 2 • Quantitative Aptitude • Q56

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The general solution of the equation tan 3x + cot(2x + π3\frac{\pi}{3}) = 0 is:

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Correct answer: D

Explanation

The correct answer is Option 4 i.e. nπ∔5π6,n∈zn\pi\dotplus\frac{5\pi}{6}, n\in z.

tan 3x + cot(2x + π/3) = 0

⇒ tan 3x = -cot(2x + π/3)

⇒ tan 3x = tan[(2x + π/3) + π/2]

⇒ tan 3x = tan(2x + 5π/6)

For tan A = tan B, the general solution is A = nπ + B, where 'n' is an integer

So, 3x = nπ + (2x + 5π/6)

⇒ 3x - 2x = nπ + 5π/6

⇒ x = nπ + 5π/6