The floor of a building consists of 600 rhombus-shaped tiles. If the lengths of the diagonals of each tile are 16 cm and 19 cm, respectively, then find the cost of polishing the floor at a rate of Rs. 10 per m².
Show answer & explanation
Correct answer: C
Explanation
Given:
Number of tiles = 600
Diagonal₁ = 16 cm
Diagonal₂ = 19 cm
Rate = ₹10/m²
By the formula:
Area of rhombus = (d₁ × d₂) / 2
Area of one tile = (16 × 19) / 2 = ₹152 cm²
Total area of 600 tiles = 152 × 600 = 91200 cm²
In meters²
= 91200 / 10000 = 9.12 m²
Polishing cost = 9.12 × 10 = ₹91.2