The expression (cos6θ + sin6θ-1)(tan2θ+cot2θ+2) is equal to:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. -3
(cos6θ + sin6θ - 1)(tan2θ + cot2θ + 2)
Put θ = 450
(cos6450 + sin6450 - 1)(tan2450 + cot2450 + 2)
= [(1/√2)6 + (1/√2)6 - 1](1 + 1 + 2)
= (1/8 + 1/8 - 1)(4)
= 4(-3/4)
= -3