SarkariPYQ

SSC CHSL 2023 PYQ — Question 71

SSC CHSL - 07 Aug 2023 - Shift 4 • Quantitative Aptitude • Q71

Back to paper

The divisor is 11 times the quotient and 5 times the remainder. If the remainder is 44, then the dividend is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 4444.

Let Quotient = Q, Divisor = D, and Dividend = N

Now, according to the question

⇒ D = 11Q.....(1)

The divisor is 5 times the remainder.

⇒ D = 5 × 44 = 220

Thus, D = 220

Now, from equation 1

⇒ 220 = 11Q

⇒ Q = 20

Now,

⇒ N = D × Q + R

⇒ N = 220 × 20 + 44

⇒ N = 4400 + 44

⇒ N = 4444