SSC CHSL 2025 PYQ — Question 69

SSC CHSL - 17 Nov 2025 - Shift 3 • Quantitative Aptitude • Q69

The distance between two parallel chords of lengths 16 cm and 12 cm in a circle of radius 10 cm is:

Show answer & explanation

Correct answer: A

Explanation

Given:

Radius of the circle = 10 cm

Chords = 16 cm and 12 cm

Formula:

Distance of the chord from the center = √(r² − (l/2)²)

For a 16 cm chord

Distance = √(10² − 8²)

= √(100 − 64)

= √36

= 6 cm

For a 12 cm chord

Distance = √(10² − 6²)

= √(100 − 36)

= √64

= 8 cm

Distance between the two chords = 8 + 6 = 14 cm

= 8 − 6 = 2 cm

2 cm or 14 cm.