The distance between two parallel chords of length 6 cm each, in a circle of diameter 10 cm is:
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Correct answer: B
Explanation
The correct answer is option 2 i.e. 8 cm.
Length of each chord = 6 cm
Diameter of circle = 10 cm ⇒ Radius (r) = 5 cm
Each chord is 6 cm ⇒ half-length = 3 cm
Let the perpendicular from center to each chord be d₁ and d₂.
Using Pythagoras:
d₁ = √(5² − 3²) = √(25 − 9) = √16 = 4 cm
Same for d₂ = 4 cm
So, total distance between the chords = d₁ + d₂ = 4 + 4 = 8 cm