The diameter of a circle is 20 cm. The length of a chord AB is 10 cm. What will be the angle made by this chord at the center of this circle?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 60°.
Radius = OA = OB = 20/2 = 10 cm
OA = OB = AB = 10 cm
ΔOAB is an equilateral triangle
So, ∠OAB = ∠OBA = ∠AOB = 180°/3 = 60°
Hence, the angle made by this chord at the center of this circle is 60°.