The diagonal of a square A is (a + b) units. What is the area (in square units) of the square drawn on the diagonal of square B whose area is twice the area of A?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e 2(a + b)2
| Understanding | Application |
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Area of square A = (diagonal)2 / 2 The area of square B is twice of A. The side of square B will be the square root of the area of the square. |
⇒ Area of square A = (a + b)2 / 2 ⇒ Area of square B = (a + b)2 ⇒ The side of square B = a + b ⇒ The diagonal will be = √2(a + b) The area will be = 2(a + b)2 |