SSC CHSL 2024 PYQ — Question 67

SSC CHSL - 03 July 2024 - Shift 2 • Quantitative Aptitude • Q67

The curved surface area of a right circular cylinder of height 14 cm, is 88 cm2. Find the total surface area of the cylinder.

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 6607\frac{660}{7} cm2.

Given that, height of right circular cylinder, h = 14 cm

Curved surface area(CSA) of cylinder = 88 cm2

Also, CSA of cylinder = 2πrh2 \pi rh

And Total surface area(TSA) of cylinder = 2πr(r+h)2 \pi r(r + h)

According to the given question,

2πrh2 \pi rh = 88

⇒ 2×227×r×142 \times {22 \over 7} \times r \times 14 = 88

⇒ r = 1 cm

Now, TSA = 2πr(r+h)2 \pi r(r + h)

⇒ TSA = 2×227×1(1+14)2 \times {22 \over 7} \times 1(1 + 14)

⇒ TSA = 2×227×152 \times {22 \over 7} \times 15

⇒ TSA = 6607660\over 7 

Hence the total surface area of the cylinder is 6607660\over 7 cm2.