The chords AB and CD of a circle intersect at E. If AE = 12 cm, BE = 20.25 cm and CE = 3 DE, then the length (in cm) of CE is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e 27.
| Understanding/Application |
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By the property, the chords of a circle which cut each other - AE × EB = DE × CE |
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12 × 20.25 = DE × 3DE ⇒ 243 = 3DE2 ⇒ DE2 = 81 ⇒ DE = 9 cm ⇒ CE = 3DE = 3(9) = 27 cm |