SSC CGL 2023 PYQ — Question 14

SSC CGL Tier II - 6 March 2023 - Shift 1 • Quantitative Aptitude • Q14

The centroid of an equilateral triangle PQR is L. If PQ = 6 cm, the length of PL is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is Option 3 i.e. 2√3 cm

Given that

The side of the equilateral triangle PQR is PQ = 6 cm

Then the height of the equilateral triangle h = √3/2 × 6 = 3√3 cm

The centroid of an equilateral triangle PQR is L.

Hence, the length of PL = (2/3) h = (2/3) × 3√3 = 2√3 cm