SSC CGL 2023 PYQ — Question 67

SSC CGL - 24 July 2023 - Shift 3 • Quantitative Aptitude • Q67

The centroid of an equilateral triangle PQR is L. If PQ = 6 cm, the length of PL is:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e.  232\sqrt{3} cm.

Circumradius of equilateral triangle = Side of equilateral triangle/√3

Since all the centers lie at the same point L, PL is also the circumradius of the equilateral triangle PQR.

PL = PQ/√3 = 6/√3 = 2√3

Therefore, the length of PL is 2√3 cm.