The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs, If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is
Show answer & explanation
Correct answer: D
Explanation
The correct option is 4.
let the score of lowest inning = x
score of highest inning = x + 172
avg of 38 innings = 48
total score of 38 innings = 48 × 38 = 1824
total score of 40 innings = 50 × 40 = 2000
x + x + 172 = 2000 - 1824
2x + 172 = 176
2x = 4
x = 2
highest score of the player = 172 + 2 = 174