SSC CHSL 2025 PYQ — Question 57

SSC CHSL - 27 Nov 2025 - Shift 2 • Quantitative Aptitude • Q57

The base of a regular right pyramid is an isosceles triangle with equal sides of 25 cm and a base of 30 cm. The slant height of the pyramid is 40 cm. Find the total surface area of the pyramid.

Show answer & explanation

Correct answer: C

Explanation

Given:

Base = isosceles triangle

Equal sides = 25 cm

Base = 30 cm

Slant height of the pyramid = 40 cm

Formula:

Total surface area of ​​the pyramid = Base area + Lateral surface area

Height of the base triangle = √(25 × 25 − 15 × 15) = 20 cm

Base area = (1/2) × 30 × 20 = 300 cm²

Lateral surface area = (1/2) × (25 + 25 + 30) × 40 = 1600 cm²

Total surface area = 300 + 1600 = 1900 cm²