The average score of nineteen students in a computer examination is 74. It was detected that while working out the average by mistake the marks secured by one student was recorded as 65 in place of 56. What is the correct average score (correct to one decimal place)?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 73.5
Formula used:
Average = Sum of observations/number of observations ---- (1)
Calculations:
According to the question;
Sum of score of 19 students = 19 × 74 = 1406
The marks secured by one student was recorded as 65 in place of 56
Correct sum of marks = 1406 - 65 + 56 = 1397
Required average = 1397/19 = 73.5