SSC CHSL 2025 PYQ — Question 55

SSC CHSL - 21 Nov 2025 - Shift 3 • Quantitative Aptitude • Q55

The average score of 4 innings is 50 runs. If the difference between the highest and lowest score is 30 and the remaining two scores are 48 and 52, find the highest score.

Show answer & explanation

Correct answer: A

Explanation

Given:

Number of innings = 4

Average score = 50

Two scores = 48, 52

Highest − lowest = 30

Formula:

Total runs = Average × Number of innings

Total runs = 50 × 4 = 200

Sum of known scores = 48 + 52 = 100

Highest + lowest = 200 − 100 = 100

Highest − lowest = 30

2 × highest = 100 + 30

2 × highest = 130

Highest = 65