The average of the squares of the first 48 natural numbers is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 792.17.
The sum of the squares of the first n natural numbers = [n(n + 1)(2n + 1)]/6
Here, n = 48
Sum = [48(48 + 1)(2 × 48 + 1)]/6 = (48 × 49 × 97)/6 = 38024
Average = 38024/48 = 792.1666... = 792.17 (approx)
Therefore, the average of the squares of the first 48 natural numbers is 792.17.