The average of the squares of the first 47 natural numbers is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 760.
The average of the square of first n natural numbers = [(n + 1)(2n + 1)]/6
= [(47 + 1)(2 × 47 + 1)]/6
= [48(94 + 1)]/6
= (48 × 95)/6
= 8 × 95
= 760
Therefore, the average of the squares of the first 47 natural numbers is 760.