The average of n numbers is 45. If 60% of the numbers are increased by 5 each and the remaining numbers are decreased by 10 each, then what is the average of the numbers so obtained?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 44
The average of 'n' number is 45.
Sum of n number = 45 × n = 45n.
60% of n = .6n
Increased in the sum = 6n × 5 = 3n
40% of n decreased by 10 = .4n × 10 = 4n
Decreased in the sum = 4n
New sum = 45n + 3n - 4n = 44n
New average = 44n/n = 44.