The average of a set of 15 numbers is 41. Five numbers 21, 24, 39, 47, and 97 are removed from the above set. What will the average of the remaining 10 numbers?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 38.7.
We know that,
Average = Sum of observations/Number of observations
Now, according to the question
Sum of 15 observations = 15 × 41 = 615
Five numbers 21, 24, 39, 47, and 97 are removed = 615 - (21 + 24 + 39 + 47 + 97) = 387
Required average = 387/10 = 38.7