The average of 4 consecutive numbers is 64.5. What is the largest number among these numbers?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 66
In the 4 consecutive numbers, let's assume the smallest number is 'y'.
So the 4 consecutive numbers will be y, (y + 1), (y + 2), (y + 3)
The average of 4 consecutive numbers is 64.5.
y + (y + 1) + (y + 2) + (y + 3) = 64.5 × 4
4y + 6 = 258
4y = 258 - 6
4y = 252
y = 63
The largest number among these numbers = =(y+3)
= (63 + 3)
= 66