The average of 19 numbers is 22.8. The average of the first ten numbers is 18.4 and that of the last ten numbers is 28.6. If the 10th number is excluded from the given numbers, then what is the average of the remaining numbers? (answer should be nearest to an integer)
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 22
The average of 19 numbers is 22.8.
⇒ sum of 19 numbers = 22.8 × 19 = 433.2
The average of the first ten numbers is 18.4.
⇒ sum of first ten numbers = 18.4 × 10 = 184
The average of the last ten numbers is 28.6.
⇒ sum of last ten numbers = 28.6 ×10 = 286
so the 10th number is =(184 + 286) - 433.2 = 36.8
If the 10th number is excluded from the given numbers, then what is the average of the remaining numbers = (433.2 - 36.8)/18 = 22.022 = nearly 22