The average of 10 consecutive integers is (11/2). What is the average of the "smallest four" of these integers?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 2.5.
If the average of the consecutive 10 integers is 11/2 i.e. 5.5, then it is also the average of the 5th and 6th integers
If the average of 5th and 6th integers is 5.5, then the 5th and 6th integer are 5 and 6
Thus, the consecutive 10 integers are 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10
We know that,
Average = Sum of observations/Number of observations
The average of smallest four = (1 + 2 + 3 + 4)/4 = 10/4 = 2.5