The areas of two similar triangles ΔPQR and ΔXYZ are 12.96 cm2 and 635.04 cm2, respectively. If QR = 2.9 cm, then the length (in cm) of YZ equals:
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Correct answer: B
Explanation
The correct answer is option 2 i.e. 20.3.
The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Therefore,
(Area of ΔPQR)/ (Area of ΔXYZ) = (QR / YZ)
12.96 / 635.04 = (2.9 / YZ).
YZ = 2.9 × 635.04 / 12.96.
YZ = 8.41× 49.25.
YZ = 414.6625.
YZ = √414.6625.
YZ ≈ 20.36 cm.
Therefore, the length of YZ is approximately 20.36 cm.