SSC Selection Post 2022 PYQ — Question 74

SSC Selection Post - Graduation Level - 9 Feb 2022 - Shift 3 • Quantitative Aptitude • Q74

The area of a triangular park, whose sides are 160 m, 300 m, and 340 m, is 4172217\over22of the area of a circular park. What is the perimeter (in m) of the circular park (correct to one decimal place)? (Take π = 22722\over7)

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 251.4.

1602 + 3002 = 3402 [Right-angled triangle]

Triangle area = (1/2) × 160 × 300 = 24000 m2

⇒ Circle Area = 24000 × (22/105) = 5028.57 m2

πr2 = 5028.57

⇒ (22/7)r2 = 5028.57

⇒ r2 = 5028.57 × (7/22) = 1600

⇒ r = 40 m

Perimeter = 2πr = 2 × (22/7) × 40 = 251.4 m