SSC CHSL 2019 PYQ — Question 55

SSC CHSL - 1st July 2019 - Shift 3 • Quantitative Aptitude • Q55

The area of a field in the shape of a regular hexagon is 2400√3 m2. What will be the cost of fencing it at Rs. 18.50 per meter?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. Rs. 4440

Concept

Understanding

Application

Fair calculation

Area of hexagon = 6 × (√3/4) (Side)2

Given

Area of hexagonal field = 2400√3 m2

Cost of fencing = Rs. 18.50 per metre

6 × (√3/4) (Side)2 = 2400√3

⇒ (Side)2 = 1600

⇒ Side = 40 m

Hence,

Perimeter = 6 × side = 240 m

Total cost of fencing = (6 x 40) x 18.50 = Rs. 4440

(6 x 40) x 18.5

= 240 x 18.5

= 4440