Suraj can complete a certain work in the same time in which Manoj and Rajesh together can complete it. If Rajesh can alone complete it in 28 days and Suraj and Manoj together can complete it in 14 days, then in how many days can Manoj alone complete it?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 56
Let the total work be LCM of 28 and 14 = 28
Rajesh's efficiency = 28/28 = 1
Suraj and Manoj's efficiency = 14/28 = 2
ATQ
Suraj's Efficiency = Manoj's efficiency + Rajesh's efficiency
Suraj's Efficiency = Manoj's efficiency + 1
Suraj's Efficiency + Manoj's efficiency = Manoj's efficiency + 1 + Manoj's efficiency
2 = 2Manoj's efficiency + 1
2Manoj's efficiency = 1
Manoj's efficiency = 0.5
Time Manoj would take to alone complete the work = 28/0.5
= 56 days