Study the given table and answer the questions that follow.
The table represents the number of candidates appeared, qualified, and selected in a national-level examination from four different schools M, N, O and P over the years 2012 to 2017,
Where A: Appeared; Q: Qualified; S:Selected
| Year | M | N | O | P | ||||||||
| A | Q | S | A | Q | S | A | Q | S | A | Q | S | |
| 2012 | 7000 | 750 | 84 | 3000 | 400 | 34 | 2000 | 250 | 27 | 1500 | 160 | 23 |
| 2013 | 5500 | 500 | 55 | 3500 | 420 | 56 | 2500 | 340 | 36 | 2500 | 290 | 56 |
| 2014 | 6500 | 455 | 42 | 3800 | 460 | 66 | 3500 | 380 | 48 | 2700 | 480 | 67 |
| 2015 | 8500 | 854 | 89 | 4500 | 485 | 72 | 4500 | 550 | 57 | 3400 | 540 | 87 |
| 2016 | 9000 | 922 | 92 | 4690 | 678 | 86 | 5670 | 660 | 68 | 3700 | 650 | 89 |
| 2017 | 9200 | 942 | 94 | 6700 | 700 | 92 | 6780 | 680 | 89 | 4500 | 670 | 93 |
For which school is the average number of candidates selected over the years the maximum?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. M.
School M: 84 + 55 + 42 + 89 + 92 + 94 = 456
Average = 456/6 = 76
School N: 34 + 56 + 66 + 72 + 86 + 92 = 406
Average = 406/6 = 67.67
School O: 27 + 36 + 48 + 57 + 68 + 89 = 325
Average = 325/6 = 54.17
School P: 23 + 56 + 67 + 87 + 89 + 93 = 415
Average = 415/6 = 69.17
Therefore, the maximum average number of candidates selected is for School M, with an average of 76.