SSC CPO 2019 PYQ — Question 133

SSC CPO Tier I - 13th December 2019 - Shift 2 • Quantitative Aptitude • Q133

Solve the following

(a + b + c) (ab + bc + ca) - abc = ?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is Option 4 i.e. (a + b) (b + c) (c + a)

Understanding Application
Tricks

(a + b + c) (ab + bc + ca) - abc

= (a2b + abc + a2c +b2a + b2c + abc + abc + bc2 + ac2) - abc

= (a2b + 2abc + a2c +b2a + b2c + bc2 + ac2)  ........i)

Now

From option

(a + b) (b + c) (c + a)

⇒ (ab + ac + b2 + bc)(c + a)

⇒ (abc + a2b +ac2 + a2c + b2c + b2a +bc2 + abc)

⇒ (2abc + a2b +ac2 + a2c + b2c + b2a +bc2) .........ii)

Hence

From eq i) and eq ii)

both are same

So

(a + b) (b + c) (c + a)