SSC CHSL 2024 PYQ — Question 56

The correct answer is Option 4 i.e. $1 {1\over8}$.

$2×2+2\over2÷2×2$ ÷ (${{1\over2}÷{1\over2}of {1\over2}}$)/($​​{1\over2}+{1\over2}of{1\over2}$).

⇒ $4+2\over1×2$ ÷ ${{1\over2}÷{1\over4}\over {1\over2}+ {1\over4}}$

⇒ $6\over2$ ÷ ${{1\over2}\times 4\over {2\over4}+ {1\over4}}$

⇒​​​​​​​ 3 ÷ ${2\over ({3\over4})}$

⇒​​​​​​​ 3 ÷ ${8\over3}$

⇒​​​​​​​ 3 × ${3\over8}$

⇒​​​​​​​ ${9\over8}$ = $1 {1\over8}$