SSC CGL 2024 PYQ — Question 65

SSC CGL - 18 Sep 2024 - Shift 3 • Quantitative Aptitude • Q65

sinAsinB=_________.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e.  121\over2 {cos(A-B) - cos(A+B)}.

sinAsinB = 121\over2{cos(A-B) - cos(A+B)}

cosAcosB = 121\over2{cos(A+B) + cos(A-B)}

sinAcosB = 12{1\over 2} {sin(A+B) + sin(A-B)}

cosAsinB = 121\over2{sin(A+B) - sin(A-B)}