SSC CHSL 2023 PYQ — Question 71

The correct answer is option 2 i.e.  $\frac{1}{sin^2A(1 - sin^2A)}$.

( 1 + tan²A)(1 + cot²A)

= sec²A × cosec²A

= (1/cos²A) × (1/sin²A)

= 1/(sin²A cos²A)

$=\frac{1}{sin^2A(1 - sin^2A)}$