SarkariPYQ

SSC Selection Post 2024 PYQ — Question 75

SSC Selection Post - Graduation Level - 20 Jun 2024 Shift 3 • Quantitative Aptitude • Q75

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Simplify the following expression: 0.72∔(0.4+0.2)+(0.4×0.2)(0.7+0.4+0.2)\frac{0.7^2\dotplus \left ( 0.4+ 0.2 \right )+\left ( 0.4\times 0.2 \right )}{\left ( 0.7+0.4 + 0.2\right )}

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Correct answer: A

Explanation

The correct answer is Option 1 i.e. 0.9.

Given, 0.72∔(0.4+0.2)+(0.4×0.2)(0.7+0.4+0.2)\frac{0.7^2\dotplus \left ( 0.4+ 0.2 \right )+\left ( 0.4\times 0.2 \right )}{\left ( 0.7+0.4 + 0.2\right )}

⇒ 0.49+0.6+0.081.3\frac{0.49 + 0.6 + 0.08}{1.3} = 0.9