SSC CGL 2023 PYQ — Question 25

The correct answer is Option 2 i.e. 2/9

$\frac{\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+\sqrt{225}}}}}}{\sqrt{16+19.25\times 4^2}}$

$=\frac{\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+15}}}}}{\sqrt{16+19.25\times 16}}$

$=\frac{\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{169}}}}}{\sqrt{16+304}}$

$=\frac{\sqrt{10+\sqrt{25+\sqrt{108+13}}}}{\sqrt{324}}$

$=\frac{\sqrt{10+\sqrt{25+\sqrt{121}}}}{18}$

$=\frac{\sqrt{10+\sqrt{25+11}}}{18}$

$=\frac{\sqrt{10+\sqrt{36}}}{18}$

$=\frac{\sqrt{10+6}}{18}$

= √16/18

= 4/18

= 2/9