SSC CHSL 2025 PYQ — Question 74

SSC CHSL - 14 Nov 2025 - Shift 3 • Quantitative Aptitude • Q74

Simplify:
(a² - b²)³ + (b² - c²)³ + (c² - a²)³ / (a - b)³ + (b - c)³ + (c - a)³.

Show answer & explanation

Correct answer: A

Explanation

Given:

((a² − b²)³ + (b² − c²)³ + (c² − a²)³) / ((a − b)³ + (b − c)³ + (c − a)³)

By formula:

If x + y + z = 0

then x³ + y³ + z³ = 3xyz

x = a − b

y = b − c

z = c − a

(a − b) + (b − c) + (c − a) = 0

(a − b)³ + (b − c)³ + (c − a)³ = 3(a − b)(b − c)(c − a)

Now in the numerator

a² − b² = (a − b)(a + b)

b² − c² = (b − c)(b + c)

c² − a² = (c − a)(c + a)

(a² − b²) + (b² − c²) + (c² − a²) = 0

(a² − b²²³ + (b² − c²²³) + (c² − a²²³) = 3(a² − b²)(b² − c²)(c² − a²)

= 3(a − b)(a + b)(b − c)(b + c)(c − a)(c + a)/ 3(a − b)(b − c)(c − a)

= (a + b)(b + c)(c + a)